May 1932 RadioCraft
[Table
of Contents]
Wax nostalgic about and learn from the history of early electronics.
See articles from RadioCraft,
published 1929  1953. All copyrights are hereby acknowledged.

Here is Part 1 of a threepart article
on attenuator pad and impedance matching articles that appeared in RadioCraft
magazine. Although the focus is on audio frequencies, the principles apply in general.
It is interesting to read about wavelengths expressed in units of miles versus feet
and meters like we are used to seeing for radio frequencies. Keep in mind that most
of the decibel formulas used here are for voltage and not for power.
The Theory and Construction of Attenuators, Line Filters and Matching
Transformers (Part I)
The Theory and Construction of Attenuators, Line Filters and Matching
Transformers (Part II)
The Theory and Construction of Attenuators and Line Filters (Part
III)
The Theory and Construction of Attenuators, Line Filters and Matching Transformers
(Part I)
Fig. 1  Circuit illustrating current distribution.
By Hy Levy, B.S.
In any welldesigned voice transmission circuit, such as telephone lines, radiobroadcast
speech equipment, publicaddress systems, "talkie" apparatus, etc., will be found
resistance networks, or attenuators, more commonly called "pads." The proper use
and design of these pads make for an efficient transmission system, from which the
maximum output of energy with the least distortion may be obtained, and which, if
these pads were not used, could not be realized. It can be said that pads find their
way into practically every phase of voice transmission where quality reproduction
is the prime requisite.
It is the purpose of this article to make clear the methods by which these pads
are designed, to show their application in transmission circuits, and to discuss
the problems encountered in transmission circuits where pads are used.
Purpose of Pads
In voicetransmission circuits, where energy is being transmitted over a line
to a load located at the far end of the line, it is necessary that some means be
employed to control the magnitude of the energy entering the load. It is for such
purposes that pads are used. These networks are always used between a source of
energy and a load. The source of energy might be any of the following:
(1) Output of a speech amplifier, such as a normally highlevel amplifier which
is feeding another amplifier located at a remote point;
(2) Output of a highlevel amplifier (power amplifier);
(3) Output of a lowlevel amplifier, such as a condensermicrophone amplifier,
which is feeding a speech amplifier located at some distant point;
(4) Output of microphone circuits, etc.: The load may consist of a transmission
line carrying the energy and terminating in an impedance located at the far end
of the line. This load impedance might consist of any of the following:
(a) Primary side of a linematching transformer (line to line transformer);
(b) Input circuit of a speech amplifier;
(c) Loud speakers located at distant points from an amplifier;
(d) Mixing circuits, etc.
Fig. 2  Schematic diagram of an "H"type pad.
Fig. 3  Impedance relations ·in a typical line.
The attenuator imposes a constant impedance upon the transmission line, thereby
controlling the level (magnitude) of the energy being transmitted into the far end
of the line. The attenuator or "pad" maintains this level by introducing a loss
in energy between the source and the load, at the same time causing no impedance
mismatch to the impedances between which it is working (source impedance and load
impedance).
To illustrate the statements given in the preceding paragraphs, a typical case
showing the use of such networks will be given. The complete design and calculation
of the pads will be shown, and the problem arising in circuits in which these pads
are used will be discussed. It is hoped that by obtaining a complete understanding
of the subject matter given in these papers, any problems relating to the design
and use of pads in voice transmission circuits will be materially lessened.
Let us assume we have a radio amplifier whose output voltage is 1.5 (effective
value of alternating current). This voltage is to be fed over. a transmission line,
at the far end of which is located the primary side of an input transformer, whose
secondary is in the input circuit of an amplifier (see Fig. 3). Let us also
assume that it is also necessary to reduce the voltage impressed across the primary
side of the transformer to approximately 0.15 volts (R.M.S.). It can be seen, therefore,
that it is necessary to interpose a network of some sort between the input source
of 1.5 volts and the primary side of the input transformer in order that the voltage
will be reduced to the desired value, at the same time introducing no impedance
mismatch between the source and the load.
In voice transmission circuits, this network is composed of nonreactive resistances
so arranged that they will cause the desired loss between the input and output terminals
of the pad. By "nonreactive" is meant resistances whose impedance remains practically
constant to alternating current. This is accomplished by constructing the resistances
so that their inductance and capacitance is negligible throughout the frequency
band in which they function. (The construction of the resistances for use in the
pads will be given in a forthcoming article).
For most purposes, this frequency band can be taken as the audio spectrum of
40 to 10,000 cycles per second. The resistances used in networks must be nonreactive
in order that the attenuator maintain constant impedance characteristics throughout
the audio band to the impedances between which it is working, so that straight line
frequency attenuation will be obtained without frequency distortion in the transmission
circuit, which would hinder the intelligibility of the signal.
The change in voltage between the source and the load is expressed as the logarithmic
ratio between the two voltages. At this point a brief resume on the transmission
unit or decibel will be given, so that those not familiar with this unit will have
a clear understanding of how it is used in transmission circuits.
In electrical circuits carrying energy which is either being amplified or attenuated,
the question arises: What is the relationship between voltage, current, and power
on the input side of an amplifier or an attenuator, to the voltage, current, and
power on its output side? The engineer signifies this ratio between two voltages,
two currents, or two powers, by the number of decibels change taking place between
the input and output terminals of the amplifier or the attenuator.
The Decibel
In any electrical circuit carrying energy, the product of the common logarithm
of the power ratio multiplied by ten, or the product of the common logarithm of
the current or voltage ratios multiplied by twenty determines the change in decibels.
As an example of this principle, let us assume that in a certain circuit the
voltage has been decreased from 3.0 volts to 1.0 volt, or to onethird of its original
value, Then from the definition as given above, the voltage ratio is 3 to 1, or
3. The common logarithm of three is 0.4771 (which may be obtained from a table of
common logarithms). This means that 0.4771 is the power to which ten must be raised
to give three. Then, multiplying 0.4771 by twenty, we get 0.9542 decibels change:
i. e., decibels change =
where V_{1} = input voltage
and V_{2} = output voltage
=
= 20 log 3.0
= 20 X 0.4771
decibels change = 9.542
Fig. 5 (top)  Openend transmission line.
Fig. 6 (bottom)  "Shorted" transmission line
The above simply means that if the voltage in the circuit has been decreased
to .onethird of its original value, we have caused a change of 9.542 units or decibels
to have taken place. (See table in November, 1931 issue of RadioCraft  Editor.)
This change in decibels is expressed as. a loss, as the voltage has been decreased.
Similarly, if the voltage had been increased to three times its original value,
the resultant change in decibels would also be 9.542, only in this case the result
would a gain. Therefore, if the voltage has been increased or decreased to three
times its original value, the resultant change in decibels is the same in both cases,
or 9.542. The only difference in the two cases is in the method of expressing the
results obtained.
When using the formulae shown below, the change in decibels obtained depends
on the type of circuit involved. In an amplifying circuit, the relationship between
the voltage, current, or power ratios is expressed as a gain in decibels. In an
attenuator, the relationship between the voltage, current, or power ratios is expressed
as a loss in decibels. In the circuits to be taken up, attenuators (resistive networks)
will be discussed, and a decrease in energy will be incurred between the terminals
of the pad, and therefore all results will be given as a loss in decibels.
Thus by expressing current, voltage, and power ratios in decibels, one has an
accurate description of the changes in energy taking place in the circuit.
From the definition of the decibel as given above, we can write the following
formulae:
Change in decibels =
where P_{1} = input power
P_{2}
= output power
V_{1}
= input voltage
V_{2}
= output voltage
I_{1}
= input current
I_{2}
= output current
This is shown in Fig. 1.
Also if we know the number of decibels change, and it is desired to determine
the voltage, current, or power ratios, we can write:
To illustrate this method, assume we wish to introduce a 15 decibel loss into
the circuit, and it is desired to know what voltage ratio will give this loss. Then
from above:
=
=
= antilog .75
= 5.62
which means that if the voltage ratio is equal to 5.62, a 15 decibel loss will
be maintained in the circuit.
Returning now to our own problem, it was determined that a network is required
to cause a loss in voltage between its terminals, from 1.5 volts, on the input side,
to 0.15 volts, on the output side. This loss expressed logarithmically is as follows:
loss in decibels =
= 20 log 10.0
= 20 x 1.0
loss in decibels = 20.0
or, a 20 decibel loss is to be incurred between the input and output terminals
of the network to be designed. This is the same as saying that by reducing the voltage
from 1.5 volts to 0.15 volts, or in the order of ten times, a loss of twenty decibels
has taken place.
The first problem to be considered is what type of network shall be used to cause
this loss in voltage.
In communication circuits, two types of networks used for this purpose are:
(1) "H"type pad
(2) "T"type pad
The Htype pad will be discussed first, and a complete discussion will be given
showing the method of obtaining the desired twenty decibel loss by the use of this
pad in our own problem.
The Htype pad is so called because it is composed of five resistances taking
the form of the letter "H". This pad is designated as a balanced network, in that
an equal number of resistances (Z1) are used in the series arms on both sides of
the line as shown in Fig. 2. In some circuits, the shunt arm Z2 may be divided
into two equal parts, with the midpoint grounded. This balances the entire network
with respect to ground.
At this point an investigation of certain factors which must be considered in
transmission circuits will be given in order that an understanding of the problems
encountered in voice transmission will be bad. It is of the utmost importance that
a general knowledge of the circuit characteristics be obtained, so that when the
design of the pads is taken up, maximum efficiency may be obtained from the transmission
line in which the pad is to be placed.
In Fig. 3 is shown the output circuit of an amplifier feeding a transmission
line, at the far end of which is located an input transformer T1.
The transformer (T2) used in the output circuit of the tube is called a tubetoline
transformer or output transformer, in that it transfers energy from the tube to
the transmission line. The secondary side of this transformer is called the source
impedance of the line, for the energy induced in this winding is the energy transmitted
along the line. This transmission line, we can assume, terminates in the primary
side of an input transformer (T1), whose secondary side is in the grid circuit of
a vacuum tube. This transformer is called a linetotube transformer or input transformer,
as it transfers the energy from the line into the tube. The primary of this transformer
is known as the load or terminating impedance, as the transmission line can be considered
as ending at this point, for the primary side completes the transmission line, and
the secondary side is considered in another circuit.
Table 2  Audio frequencies versus harmonic wavelengths.
In communication circuits the source and load impedances of the transmission
line have been standardized in most cases to 200, 500, and 600 ohm lines. Therefore.
if ZS, the source impedance, equals 200 ohms, then the load impedance ZL must also
equal 200 ohms in order to prevent socalled "reflection" losses from being set
up in the circuit. It is these "reflection" losses that will now be discussed.
Reflection Losses
The speed with which electromagnetic waves travel is the same as that of light,
or approximately 186,000 miles per second. This speed is attained only in a circuit
having zero losses, which of course is not obtainable in practice. All circuits
have some losses, and in transmission lines these losses increase as the frequency
increases. The speed of the transmitted waves is retarded slightly by the losses
of the line, and by what is known as "skin effect" of the line conductors. (Skin
effect is the forcing of the current to flow along the outer surfaces of the conductors.)
As the frequency increases, the inductance inside the conductor (mostly in the center)
increases, thereby offering a greater opposition to the flow of current within the
conductor, and consequently the current is forced to travel along the outer surface
of the wires. The relationship which exists between inductance, capacitance, and
the velocity of light is:
where V = velocity of light in miles per second
L = inductance in henries
C = capacitance in farads
If a frequency of 100 cycles per second is impressed upon a circuit of infinite
length (no end), at the end of 1/1000 of a second the wave will have traveled 186000/1000
or 186 miles.
A part of such a wave is shown in Fig. 4. This circuit is said to have a
full wavelength for the frequency of 1000 c.p.s. (cycles per second). In this circuit,
when the first part of the waves arrives at a point 186 miles distant from the start
of the transmission line, the end of the. same wave is at the start of the circuit.
This is assuming zero losses in the line. The actual wave would be slightly retarded
due to the losses of the circuit. This is shown in the dotted lines of Fig. 4.
If now an alternatingcurrent wave is impressed upon a transmission line, it
will travel along the line with the speed of light, until it reaches the far end
of the line, where, if the far end is open (infinite impedance), the wave will be
reflected back to its origin with the same velocity, but will gradually decrease
in magnitude as it approaches the starting point of the line, due to the losses
of the line which it encounters. If at the moment this wave reaches the starting
point another wave is sent into the line, that which was left of the first wave
adds itself to the second wave and therefore increases the second wave. If, at the
moment that the returned second wave reaches the starting point, a third wave is
sent into the circuit, that which was left of the second wave adds itself to the
third wave and so on as the number of waves increases; with the result that an accumulative
effect of energy is developed in the circuit. The magnitude to which this reflected
energy can rise is determined by a characteristic of the line conductors known as
the "surge impedance."
The surge impedance of a conductor is the impedance which the conductor offers
to these free oscillations of energy at the high frequency limit. (This condition
is greatest at the highest frequency that the circuit passes.) This building up
of reflected energy in the circuit is known as "quarterwave resonance," or merely
as the resonant frequency of the line. To produce such a condition, it is necessary
that the alternatingcurrent impulses occur at intervals of time equal to the time
necessary for the energy to travel the length of the line and back. In other words,
for one complete cycle (two impulses) the energy would have to travel the length
of the line four times between successive impulses in order to create resonance.
Expressed as a formula:
frequency =
or, length in miles =
Table 1  Audio frequency and wavelength.
It can be seen, therefore, that as the frequency increases the length of the
circuit becomes shorter in order to produce the resonant condition. In table 1 is
given the length of circuits in miles to produce resonance throughout the audio
band.
At this condition of resonance, the magnitude of the reflected energy reaches
a maximum; and abnormal voltages and currents are set up in the circuit. This reflected
energy, if present in a circuit in which vacuum tubes are employed., will cause
incorrect voltages to be applied to the grids of the tubes, which in turn will cause
distortion of the waveform of the of the original signals, with the result that
harmonics will be generated in the circuit. As these harmonics increase, the resonant
period of the circuit is decreased. This is shown in table 2, where the resonant
periods of circuits due to harmonics being set up in the line are given. It can
readily be seen that as the harmonics increase, the length of the line necessary
to produce resonance is decreased.
Now in practical circuits, such as the transmission lines encountered in everyday
sound work, the resonant condition may not be theoretically reached as the fundamental
frequencies used are not high enough to produce resonance for the length of the
lines ordinarily used, which in most cases are comparatively short. Nevertheless,
if the lines are not properly terminated, the reflected energy which is set up produces
distortion of the waveform of the original impulses, which in turn will create
harmonics. These harmonics are multiples of the fundamental frequencies, and as
these harmonics increase, the frequency of the circuit increases, thereby approaching
the resonant frequency of the line. .Consequently, as the resonant period of the
line is approached, extreme distortion of the signals arises, with the result that
the quality is atrocious.
Mechanical Analogy
The analysis of reflected electrical waves is analogous to that of water flowing
in a canal. If the near end of a canal is struck a blow, a waterwave will be set
up which will travel to the end of the canal, where it will be reflected back to
the origin. As it travels back toward the starting point, its amplitude will decrease
slowly, due to resistance encountered in the canal. If, at the instant the wave
reaches the origin, another blow is struck, a second wave will flow to the end of
the canal and return. This second wave will be composed of itself, plus that which
was left of the first wave. This effect increases as the number of waves is increased,
and reaches a maximum when the losses due to resistance prevent the amplitude of
the waves from increasing further.
If a gate or obstruction of some sort is inserted at the end of the canal, any
waves traveling down the canal will strike the wall and bank up to a height determined
by the potential energy of the wave. When the potential energy equals the kinetic
energy impressed on the wall, the wave will have reached its maximum height. It
can be shown that in certain cases the waves will rise to a height twice that of
the original wave striking the wall, and then will be reflected back at a slowly
decreasing amplitude as the starting point is approached.
Similarly, in electrical circuits, when an electromagnetic wave reaches the end
of a transmission line, and the line is open at the far end as shown in Fig. 5,
the wave is reflected back to the source; the current is zero, and the voltage at
the load reaches a value equal to twice the peak value of the original voltage.
Also, if instead of open circuiting the far end of the line, it is short circuited,
the wave is reflected with a current value twice the value of the starting current,
and the voltage becomes zero. This is shown in Fig. 6.
Posted August 18, 2020(original
11/16/2015)
