April 1959 Popular Electronics
Wax nostalgic about and learn from the history of early electronics. See articles
published October 1954 - April 1985. All copyrights are hereby acknowledged.
Here is another of the Electronic
Sticklers challenges from Popular Electronics magazine (see May
Sticklers). These are fairly basic circuit analysis problems that often can
be solved by inspection, but sometimes a pencil and paper are necessary. Re-drawing
the circuit in a different configuration to make the connections more obvious often
helps when solving total resistance, capacitance, inductance, etc., as in question
#1. In this case, though, you need to be able to recognize a common configuration
to be able to simplify the circuit; otherwise, you'll be writing and solving mesh
equations. #2 has a simple answer and a more elaborate possibility. #3 and #4 are
simple inspection problems.
These four thought-twisters are arranged in order of increasing difficulty.
1) Harvey Matrix discovered this network covered
with solder, in his junk box (above). Rather than trust his ancient ohmmeter, he
tried unsuccessfully to compute the resistance mathematically. Show Harvey you are
slicker and quicker by solving the problem in one minute.
2) Joe Whatsit had a black box with only two terminals showing (above). To find
out what was in the box, Joe connected a 1 1/2-volt dry cell to the two terminals
and noted the current flow. He then connected a second identical dry cell in series
with the first cell and repeated the experiment. The same current was noted. With
this information, Joe figured out what was in the box. Can you?
3) Mr. Pennypincher, in order to save money on batteries for his portable radio,
built this little voltage supply (to the right) to substitute for the batteries.
When he plugged in the unit, he was running a risk of a blown-out component. Any
4) With the setup shown (to the left), a diode in series with a capacitor, Harold
Tinkertoy applied 100 volts r.m.s. across the circuit. Then he used his vacuum-tube
voltmeter to measure the peak voltage across the diode. How much did he measure?
To make the problem easy, assume that a sine wave is applied to the circuit.
--Louis E. Garner, Jr.
Answers to Electronic: Sticklers
1. Two ohms. Redraw the network schematic in the form of a bridge circuit. You
will find that the resistance values of the bridge legs result in a balanced bridge.
Hence the 3-ohm resistor is an inactive component and can be omitted from the circuit.
All that remains are two series resistance circuits in parallel.
2. A short circuit. The current remains the same since the two dry cells provide
not only twice the voltage but also twice the internal resistance. (Kirt note: It
could also contain a constant current circuit)
3. Since there is no surge resistor, the charging current of the capacitor would
pull too much current through the rectifier. Without the surge resistor (20 cents),
there's a good chance the rectifier ($1.00) would burn out.
4. About 282 volts! How come? On one half-cycle, when the diode's plate is positive,
the capacitor charges to peak line voltage... or about 141 volts (1.41 multiplied
by line voltage). On the next half cycle, the capacitor's voltage is in series with
the peak line voltage and thus adds to it... and 141 plus 141 equals 282! This arrangement,
incidentally, is basic to voltage-doubler power supply design.
If you know of a tricky Electronic Stickler, send it with the solution to the
editors of POPULAR ELECTRONICS. If it is accepted, we will send you a $5 check.
Write each Stickler you would like to submit on the back of a postcard. Submit as
many postcards as you like but, please, just one Stickler per postcard. Send to:
POPULAR ELECTRONICS STICKLERS, One Park Ave., New York 16, N. Y. Sorry, but we will
not be able to return unused Sticklers.
Posted March 1, 2019