Hi again out there
As far as I could find in my physics book the heating of a copper wire with known weight from its diameter and length, a known applied power and time will be: dT = (P*t)/(m*c) and T1 = T0 + dT
P=1W, t=3600s (60min), m=1kg, T0=25 degC and c=387 J/(Kg*K) gives
dT = 9.3 and T1=34.3 degC.
Fine, but what if one has to account for the heat conductance and heat radiation from the wire (natural air cooling) - then what will the final temperature be in degrees Celcius?