Thank you for visiting RF Cafe! Electronics World Cover,TOC,and list of posted Popular Electronics articles QST Radio & TV News Radio-Craft Radio-Electronics Short Wave Craft Wireless World About RF Cafe RF Cafe Homepage RF Cafe in Morse Code Google Search of RF Cafe website Sitemap Electronics Equations Mathematics Equations Equations physics Manufacturers & distributors Engineer Jobs Twitter LinkedIn Crosswords Engineering Humor Kirt's Cogitations Engineering Event Calendar RF Engineering Quizzes AN/MPN-14 Radar 5CCG Notable Quotes App Notes Calculators Education Magazines Software,T-Shirts,Coffee Mugs Articles - submitted by RF Cafe visitors Simulators Technical Writings RF Cafe Archives Test Notes Wireless System Designer RF Stencils for Visio Shapes for Word Search RF Cafe Sitemap Advertising Facebook RF Cafe Forums RF Cafe Homepage Thank you for visiting RF Cafe!

Please Reply---Output Match in PA - RF Cafe Forums

The original RF Cafe Forums were shut down in late 2012 due to maintenance issues. Original posts:

Amateur Radio | Antennas | Circuits & Components | Systems | Test & Measurement


kris
Post subject: please reply---output match in PA Posted: Sun Jan 08, 2006 2:22 am
i know i've been asking a few questions and i really appreciate all the answer....i'm a student learning and i've one more question to ask.

i did loadpull analysis and i found out that I need a load of X+jY. so what i did i just transformed a 50 ohm load to X+jY using the matching utility in ADS and it seemed to work. now when i put it in the circuit it doesn't match all that well. when i am running s-param simulation i terminate in 50 ohms since i'm transforming 50 ohms to X+jY, right? if not please explain how a match can be verified for optimal load match? Just wanted to make sure. the thing that is confusing me is that the output is taken from the collector and there is a certain output impedance....if you were doing the usual conjugate match then it is clear to me but here it's not conjugate match but instead the transistor needs to see a certain load (X+jY) and i do that by transforming 50 ohms to this X+jY value...because of this i don't understand what the output reflection coefficient is calculating or reprsenting?? the thing is if i try to tune the components of output match in ADS then this would eventually lead to "conjugate match" and not a match to X+jY because as I said the output is connected to collector and after a matching network is terminated in 50 Ohms.

also the way i did output match was to take the X+jY impedance and then do the usual standard method of matching 50 ohms to X+jY...this is how you do it, right? please reply, your help will be very much required




Posted  11/12/2012

RF Cafe Software

   Wireless System Designer - RF Cafe
Wireless System Designer

RF & EE Symbols Word
RF Stencils for Visio
Calculator Workbook
RF Workbench
Smith Chartâ„¢ for Visio
Smith Chartâ„¢ for Excel

About RF Cafe

Kirt Blattenberger - RF Cafe WebmasterCopyright
1996 - 2022
Webmaster:
Kirt Blattenberger,
 BSEE - KB3UON

RF Cafe began life in 1996 as "RF Tools" in an AOL screen name web space totaling 2 MB. Its primary purpose was to provide me with ready access to commonly needed formulas and reference material while performing my work as an RF system and circuit design engineer. The Internet was still largely an unknown entity at the time and not much was available in the form of WYSIWYG ...

All trademarks, copyrights, patents, and other rights of ownership to images and text used on the RF Cafe website are hereby acknowledged.

My Hobby Website:
 AirplanesAndRockets.com

Try Using SEARCH
to Find What You Need. 
There are 1,000s of Pages Indexed on RF Cafe !

height-line