Because of the high maintenance needed to monitor and filter spammers from the RF Cafe Forums, I decided that it would
be best to just archive the pages to make all the good information posted in the past available for review. It is unfortunate
that the scumbags of the world ruin an otherwise useful venue for people wanting to exchanged useful ideas and views.
It seems that the more formal social media like Facebook pretty much dominate this kind of venue anymore anyway, so if
you would like to post something on RF Cafe's
page, please do.
Below are all of the forum threads, including all
the responses to the original posts.
Post subject: please reply---output match in PA Posted: Sun Jan 08, 2006 2:22 am
i know i've
been asking a few questions and i really appreciate all the answer....i'm a student learning and i've one more
question to ask.
i did loadpull analysis and i found out that I need a load of X+jY. so what i did i just
transformed a 50 ohm load to X+jY using the matching utility in ADS and it seemed to work. now when i put it in
the circuit it doesn't match all that well. when i am running s-param simulation i terminate in 50 ohms since i'm
transforming 50 ohms to X+jY, right? if not please explain how a match can be verified for optimal load match?
Just wanted to make sure. the thing that is confusing me is that the output is taken from the collector and there
is a certain output impedance....if you were doing the usual conjugate match then it is clear to me but here it's
not conjugate match but instead the transistor needs to see a certain load (X+jY) and i do that by transforming 50
ohms to this X+jY value...because of this i don't understand what the output reflection coefficient is calculating
or reprsenting?? the thing is if i try to tune the components of output match in ADS then this would eventually
lead to "conjugate match" and not a match to X+jY because as I said the output is connected to collector and after
a matching network is terminated in 50 Ohms.
also the way i did output match was to take the X+jY impedance
and then do the usual standard method of matching 50 ohms to X+jY...this is how you do it, right? please reply,
your help will be very much required