# Basic Part Deux - RF Cafe Forums

The original RF Cafe Forums were shut down in late 2012 due to maintenance issues. Original posts:

whatanohm
Post subject: basic part deux
Unread postPosted: Wed Sep 15, 2004 3:56 am

ok next question

10v supply going to 2 series resistors the first one is a 10ohm, but the second one is blank . what will the value be for max power transfer and what wil that power be? I know P=(I*I)(R) and that is about all i know

thanks for any help

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Unread postPosted: Wed Sep 15, 2004 12:37 pm

If the power transfer is to the second resistor (ie no 3rd resistor exists) it's a well known fact that maximum power transfer occurs for matched impedences (R2 = R1 = 10ohm)
The power dissipated in that resistor is then simply ((V/2)^2)/R due to the voltage dividing effect, where V is the input voltage.

Posted  11/12/2012

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