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Post subject: basic part deux
Unread postPosted: Wed
Sep 15, 2004 3:56 am
ok next question
10v supply going
to 2 series resistors the first one is a 10ohm, but the second one is
blank . what will the value be for max power transfer and what wil that
power be? I know P=(I*I)(R) and that is about all i know
thanks for any help
Unread postPosted: Wed Sep 15, 2004 12:37 pm
If the power transfer
is to the second resistor (ie no 3rd resistor exists) it's a well known
fact that maximum power transfer occurs for matched impedences (R2 =
R1 = 10ohm)
The power dissipated in that resistor is then simply
((V/2)^2)/R due to the voltage dividing effect, where V is the input