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Whats best for amplifier efficiency... Large V or small V ? - RF Cafe Forums

Because of the high maintenance needed to monitor and filter spammers from the RF Cafe Forums, I decided that it would be best to just archive the pages to make all the good information posted in the past available for review. It is unfortunate that the scumbags of the world ruin an otherwise useful venue for people wanting to exchanged useful ideas and views. It seems that the more formal social media like Facebook pretty much dominate this kind of venue anymore anyway, so if you would like to post something on RF Cafe's Facebook page, please do.

Below are all of the forum threads, including all the responses to the original posts.


JED928
Post subject: Whats best for amplifier efficiency... Large V or small V ?
Unread postPosted: Wed Oct 06, 2004 11:42 am

If I run an amplifier with a large DC supply rail (lets say 12 Volts) as opposed to a small supply rail (lets say 3 Volts) then for the same RF power output the currents flowing around are going to very much smaller in my 12Volt system than if I had operated with the 3 volt rail. With this in mind I then think (maybe incorrectly) that the losses in my high voltage system must be much lower than the 3 volt system (I am assuming I squared R loss dominates). I am not sure if the assumption that I squared R loss is the dominant mechanism generally but I would imagine that it is for most HF,VHF and UHF to say 1GHz amplifiers ? Now if this is all sound thinking........why are we seeing lots more lower voltage transistors and less and less of the higher voltage ones?

Of course there is the argument of where you get a large supply rail from if limited to small voltage batteries or a low supply rail but then you can always add a switch mode step up converter!

Anyone care to comment on all this?


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Itay
Post subject:
Unread postPosted: Wed Oct 06, 2004 12:46 pm

Greetings,

From what I understood you are dealing with a low power amplifier eg MMIC or Transistor. Amplifier efficiency can be calculated by the ratio: Pac/Pdc. The amplifier has to draw a constant current which is the bias current. You can set this current by a voltage drop resistor, which can be calculated by: R=(Vrail-Vd)/Ibias, where Vd is the device voltage. If you use a high rail voltage then the overall circuit effiency is degraded due to the power dissipated on the resistor, however the efficiency of the amplifier will remain the same. if you draw more output power from the amplifier then you will increase the efficiency.

I hope this helps,

Itay


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JED928
Post subject:
Unread postPosted: Thu Oct 07, 2004 8:25 am

Thats all fine but I am thinking more in terms of class B or C. In these cases you dont have a bias resistor in the emitter! Since my last post the only other thing I can think that would be a reason to run a lower supply voltage is the benefit to impedance matching. From the basic theory for class C amplfiers with a collector choke the required impedance at the transistor collector is approximately VCC^2/(2xPload) So from this equation you can adjust VCC to get your required impedance as near as possible to 50 ohms (assuming a 50 ohm system). You then do not need to impedance match (apart from a bit of reactive cancellation).

Apart from the above argument I still do not see why we are seeing so many low voltage transistors around!




Posted  11/12/2012
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