adamzaman Post subject: RLC circuit Unread postPosted: Wed
Mar 16, 2005 8:30 am
Ok, I am having a problem with a RLC
circuit and my teacher was unable to offer a satisfactory explanation.
Hope that you'll help. Consider a DC battery, a switch, a resistor,
a capacitor and an inductor in series. Before t=0 the switch is
open and assume that the circuit has achieved steady state. This
means that the capacitor voltage is 0 and so is the inductor current.
At t=0 the switch is closed. It follows that at t=0+ (i.e. just
after t=0) the capacitor voltage will be 0 and so will the inductor
current. It also follows that the voltage across the inductor at
t=0+ will be V, i.e. the voltage of the source (the capacitor is
acting as shortcircuit and the inductor as open circuit). Therefore
the rate of change of current in the circuit at t=0+ will be some
positive value (from v=L di/dt). But the rate at which the capacitor
voltage is increasing is ZERO at t=0+ (from i=C dv/dt; i=0). How
could the rate of increase of current in the inductor be nonzero,
but the rate of increase of voltage in the capacitor be zero? If
one is increasing, shouldn't the other as well? Please explain
in physical terms and not mathematical. I'll be highly grateful.
Top
Guest Post subject: Unread postPosted:
Wed Mar 16, 2005 5:28 pm
"Therefore the rate of change of
current in the circuit at t=0+ will be some positive value (from
v=L di/dt). But the rate at which the capacitor voltage is increasing
is ZERO at t=0+ (from i=C dv/dt; i=0)."
How do you get this
statement? There is current charging the capacitor the moment the
switch is flipped. It is limited by R but it is not 0.
Posted 11/12/2012
