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Below are all of the forum threads, including all
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Post subject: RLC circuit
Unread postPosted: Wed Mar 16, 2005 8:30 am
Ok, I am
having a problem with a RLC circuit and my teacher was unable to offer a satisfactory explanation. Hope that
Consider a DC battery, a switch, a resistor, a capacitor and an inductor in series. Before t=0 the
switch is open and assume that the circuit has achieved steady state. This means that the capacitor voltage is 0
and so is the inductor current. At t=0 the switch is closed. It follows that at t=0+ (i.e. just after t=0) the
capacitor voltage will be 0 and so will the inductor current. It also follows that the voltage across the inductor
at t=0+ will be V, i.e. the voltage of the source (the capacitor is acting as short-circuit and the inductor as
open circuit). Therefore the rate of change of current in the circuit at t=0+ will be some positive value (from
v=L di/dt). But the rate at which the capacitor voltage is increasing is ZERO at t=0+ (from i=C dv/dt; i=0). How
could the rate of increase of current in the inductor be non-zero, but the rate of increase of voltage in the
capacitor be zero? If one is increasing, shouldn't the other as well?
Please explain in physical terms and not
mathematical. I'll be highly grateful.
Wed Mar 16, 2005 5:28 pm
"Therefore the rate of change of current in the circuit at t=0+ will be some
positive value (from v=L di/dt). But the rate at which the capacitor voltage is increasing is ZERO at t=0+ (from
i=C dv/dt; i=0)."
How do you get this statement? There is current charging the capacitor the moment the
switch is flipped. It is limited by R but it is not 0.