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Multiplying two signals with opposite phases. - RF Cafe Forums

The original RF Cafe Forums were shut down in late 2012 due to maintenance issues. Original posts:

Amateur Radio | Antennas | Circuits & Components | Systems | Test & Measurement


nevershadow
 Post subject: Multiplying two signals with opposite phases.
Posted: Wed Jul 18, 2012 5:31 am 
 
Lieutenant

Joined: Wed Jul 18, 2012 5:13 am
Posts: 1
Hi, im new to this forum and i am not sure i am posting this question in the right place but here it goes.
If i have two baseband signals- u1(t) = A1(t)cos(wt+p(t)) and u2(t) = A2(t)cos(wt-p(t)),
where A1 and A2 are the amplitude changes in time in its band(which is 100 MHz for example) and p(t) is the phase changes in time in their band.
both signals reside in frequency - w. so they basicly overlap if put together.
now we multiply the first on the second and filter out the low frequencies - so basicly we receive
A1(t)*A2(t)cos(2wt).

my question is this- if i mentally divide u1 by half (take the first 50 MHz of the band) and u2 by half and then multiply all 4 halfs between themselves (and take hgher frequencies) will i receive the initial output - A1(t)*A2(t)cos(2wt)?

Thanks in advance.




Posted  11/12/2012

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