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Multiplying two signals with opposite phases. - RF Cafe Forums

Because of the high maintenance needed to monitor and filter spammers from the RF Cafe Forums, I decided that it would be best to just archive the pages to make all the good information posted in the past available for review. It is unfortunate that the scumbags of the world ruin an otherwise useful venue for people wanting to exchanged useful ideas and views. It seems that the more formal social media like Facebook pretty much dominate this kind of venue anymore anyway, so if you would like to post something on RF Cafe's Facebook page, please do.

Below are all of the forum threads, including all the responses to the original posts.


 Post subject: Multiplying two signals with opposite phases.
Posted: Wed Jul 18, 2012 5:31 am 
 
Lieutenant

Joined: Wed Jul 18, 2012 5:13 am
Posts: 1
Hi, im new to this forum and i am not sure i am posting this question in the right place but here it goes.
If i have two baseband signals- u1(t) = A1(t)cos(wt+p(t)) and u2(t) = A2(t)cos(wt-p(t)),
where A1 and A2 are the amplitude changes in time in its band(which is 100 MHz for example) and p(t) is the phase changes in time in their band.
both signals reside in frequency - w. so they basicly overlap if put together.
now we multiply the first on the second and filter out the low frequencies - so basicly we receive
A1(t)*A2(t)cos(2wt).

my question is this- if i mentally divide u1 by half (take the first 50 MHz of the band) and u2 by half and then multiply all 4 halfs between themselves (and take hgher frequencies) will i receive the initial output - A1(t)*A2(t)cos(2wt)?

Thanks in advance.




Posted  11/12/2012
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